SOLUTION: a tour bus leaves sacremento every friday evening at 5:00 pm for a 270 mile trip to las vegas. this week, however, the bus leaves at 5:30 pm. to arrive in las vegas on time, the dr

Algebra ->  Finance -> SOLUTION: a tour bus leaves sacremento every friday evening at 5:00 pm for a 270 mile trip to las vegas. this week, however, the bus leaves at 5:30 pm. to arrive in las vegas on time, the dr      Log On


   



Question 1170046: a tour bus leaves sacremento every friday evening at 5:00 pm for a 270 mile trip to las vegas. this week, however, the bus leaves at 5:30 pm. to arrive in las vegas on time, the driver drives 6 mph faster than usual. what is the buses usual speed ?
Answer by ikleyn(52777) About Me  (Show Source):
You can put this solution on YOUR website!
.

Let x be that unknown regular speed under the question.


Then you have this "time" equation

    270%2Fx - 270%2F%28x%2B6%29 = 0.5  of an hour  (or 30 minutes).     (1)



You may multiply both sides by x*(x+6); reduce to the standard form quadratic equation and then solve it to find x.



I will solve this equation MENTALLY.

For it, I will multiply both sides by 2. I will get then

    540%2Fx - 540%2F%28x%2B6%29 = 1,


and then the solution  x= 54 becomes OBVIOUS.



ANSWER.  The regular speed is 54 miles per hour.


CHECK.  Then equation (1)  takes the form  270%2F54 - 270%2F60 =  5 - 4.5 = 0.5  hour, confirming the answer.

Solved.